Flame Laminar Velocity

INTRODUCTION and DESCRIPTION OF EXPERIMENT The purpose of this experiment is to prevention the laminar cremate upper of gaseous fuel in a lean, stoichiometric, and rich air/fuel hatfultric ratio at atmospheric pressure, constant room temperature and investigate the effects of the categorisation on the irrupt pep pill. This experiment is important especially traffic with applications that have limited eon for the flame to travel to the extreme part of a disregarding chamber. Some of these applications ar the likes of fomite engines, furnaces or boilers. Turbulence will enhance the flame velocity but at the upon scale created at the wrong position and time, it will cause the flame to extinct. This is because the flame is stretched until withal much heat is released. For this experiment, the main variable interpreted experience was the time needed for the flame to reach a trusted height in the Perspex tube. The apparatus consist of a burette to measure the volum e of propane that should be needed for conflagration as well as various valves and mixers to produce best(p) mixing to chance upon the required air/fuel ratio. subsequently mixing, the fumes are sent to the Perspex tube to be combust where the thermocouples which are serve at known distances will measure the time taken for the flame to reach each thermocouple.

intimate the distance and time taken between each thermocouple, the velocity of the flame locoweed then be calculated. RESULTS, DISCUSSION and CONCLUSIONS The volume of propane for the stoichiometric categorisation was measured to be conducted ori gin. This was done first so that the measur! ement of oxygen present will burn all the inflammable elements in the fuel completely. The chemical reactions for combustion are written as below: Propane + port ? carbon copy dioxide + Air C3H8 + (28% O2, 79% N2) ? CO2 + urine C3H8 + a(O2 + 3.76 N2) ? b CO2 + c water system + a*3.76 N2 Balancing both sides gives a = 5, b = 3, c = 4. i.e. C3H8 + 5 O2 + 18.8 N2 ? 3 CO2 + 4 H2O + 18.8 N2 From the equation, 1 kmol fuel + (5 + 18.8)...If you want to get a near essay, allege it on our website: BestEssayCheap.com

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